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4x^2-100x^2+9=0
We add all the numbers together, and all the variables
-96x^2+9=0
a = -96; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·(-96)·9
Δ = 3456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3456}=\sqrt{576*6}=\sqrt{576}*\sqrt{6}=24\sqrt{6}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-24\sqrt{6}}{2*-96}=\frac{0-24\sqrt{6}}{-192} =-\frac{24\sqrt{6}}{-192} =-\frac{\sqrt{6}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+24\sqrt{6}}{2*-96}=\frac{0+24\sqrt{6}}{-192} =\frac{24\sqrt{6}}{-192} =\frac{\sqrt{6}}{-8} $
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